4x^2+(x-7)(x-1)=-7

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Solution for 4x^2+(x-7)(x-1)=-7 equation: 



4x^2+(x-7)(x-1)=-7

We move all terms to the left:

4x^2+(x-7)(x-1)-(-7)=0

We add all the numbers together, and all the variables

4x^2+(x-7)(x-1)+7=0

We multiply parentheses ..

4x^2+(+x^2-1x-7x+7)+7=0

We get rid of parentheses

4x^2+x^2-1x-7x+7+7=0

We add all the numbers together, and all the variables

5x^2-8x+14=0

a = 5; b = -8; c = +14;
Δ = b2-4ac
Δ = -82-4·5·14
Δ = -216
Delta is less than zero, so there is no solution for the equation

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